1/5(x-3)^2=7

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Solution for 1/5(x-3)^2=7 equation: 



1/5(x-3)^2=7

We move all terms to the left:

1/5(x-3)^2-(7)=0



Domain of the equation: 5(x-3)^2!=0

x∈R



We multiply all the terms by the denominator


-7*5(x-3)^2+1=0

Wy multiply elements

-35x(x+1=0

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